((x^2-4)/(5x))*((30)/(3x-6))

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Solution for ((x^2-4)/(5x))*((30)/(3x-6)) equation: 


D( x )

3*x-6 = 0

5*x = 0

3*x-6 = 0

3*x-6 = 0

3*x-6 = 0 // + 6

3*x = 6 // : 3

x = 6/3

x = 2

5*x = 0

5*x = 0

5*x = 0 // : 5

x = 0

x in (-oo:0) U (0:2) U (2:+oo)

((x^2-4)/(5*x))*(30/(3*x-6)) = 0

(30*(x^2-4))/(5*x*(3*x-6)) = 0

( 30 )

30 = 0

x belongs to the empty set

( x^2-4 )

1*x^2 = 4 // : 1

x^2 = 4

x^2 = 4 // ^ 1/2

abs(x) = 2

x = 2 or x = -2

x in { 2} 

x = -2

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